Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.1 Systems of Linear Equations - 9.1 Exercises - Page 857: 26

Answer

$$\left\{ {\left( {2, - 3} \right)} \right\}$$

Work Step by Step

$$\eqalign{ & 5x + 4y\,\,\,\, + \,\,\,\,2 = 0\,\,\left( {\bf{1}} \right) \cr & 4x - 5y - \,\,\,\,23 = 0\,\,\left( {\bf{2}} \right) \cr & {\text{Multiply the equation }}\left( {\bf{1}} \right){\text{ by 5 and the equation }}\left( {\bf{2}} \right){\text{ by 4}} \cr & 25x + 20y\,\,\,\, + \,\,\,\,10 = 0\,\, \cr & 16x - 20y\,\,\,\,\,\, - 92 = 0\,\, \cr & {\text{Add both equations}} \cr & 25x + 20y\,\,\,\, + \,\,\,\,10 = 0\,\, \cr & 16x - 20y\,\,\,\,\,\, - 92 = 0\,\, \cr & - - - - - - - - - - - \cr & 41x + 0 - 82 = 0 \cr & x = \frac{{82}}{{41}} \cr & x = 2 \cr & {\text{Substitute }}x = 2{\text{ into the equation }}\left( {\bf{1}} \right) \cr & 5\left( 2 \right) + 4y\,\,\,\, + \,\,\,\,2 = 0 \cr & 4y = - 12 \cr & y = - 3 \cr & \cr & {\text{The solution set is}} \cr & \left\{ {\left( {2, - 3} \right)} \right\} \cr} $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.