Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - 8.8 Parametric Equations, Graphs, and Applications - 8.8 Exercises - Page 829: 6

Answer

D

Work Step by Step

We are given that $t=\dfrac{\pi}{4}$. In order to get the values of $x$ and $y$, we need to substitute the value of $t$ in the expression of $x$ and $y$. $x= \cos (\dfrac{\pi}{4}) =\dfrac{1}{\sqrt 2}=\dfrac{\sqrt 2}{2} $ and $y=\sin (\dfrac{\pi}{4}) =\dfrac{1}{\sqrt 2}=\dfrac{\sqrt 2}{2} $ Thus, we have: $(x,y)=(\dfrac{\sqrt 2}{2}, \dfrac{\sqrt 2}{2})$ This matches with option $D$.
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