Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - 8.2 The Law of Cosines - 8.2 Exercises - Page 771: 74

Answer

$$1{\text{ sq unit}}$$

Work Step by Step

$$\eqalign{ & {\text{From the triangle we have:}} \cr & C = {45^ \circ } \cr & b = 2\,\,\,\,\,h = 1 \cr & {\text{Find the area of the triangle using the formula }}A = \frac{1}{2}bh \cr & Area = \frac{1}{2}\left( 2 \right)\left( 1 \right) \cr & Area = 1{\text{ sq unit}} \cr & {\text{Find the area of the triangle using the formula }}A = \frac{1}{2}ab\sin C \cr & {\text{With }}b = \sqrt 2 {\text{ and }}a = 2 \cr & Area = \frac{1}{2}\left( 2 \right)\left( {\sqrt 2 } \right)\sin \left( {{{45}^ \circ }} \right) \cr & Area = \left( {\sqrt 2 } \right)\left( {\frac{{\sqrt 2 }}{2}} \right) \cr & Area = 1{\text{ sq unit}} \cr & {\text{Both results are the same}} \cr} $$
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