Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - 8.2 The Law of Cosines - 8.2 Exercises - Page 767: 33

Answer

$$a = 15.7{\text{m}},{\text{ }}B = {21.6^ \circ },\,\,C = {45.6^ \circ }$$

Work Step by Step

$$\eqalign{ & A = {\text{112}}.{\text{8}}^\circ ,\,\,b = {\text{6}}.{\text{28 m}},\,\,c = {\text{12}}.{\text{2 m}} \cr & {\text{Use the Law of cosines to find }}a \cr & {a^2} = {b^2} + {c^2} - 2bc\cos A \cr & {\text{Substitute}} \cr & {a^2} = {\left( {{\text{6}}.{\text{28}}} \right)^2} + {\left( {{\text{12}}.{\text{2}}} \right)^2} - 2\left( {{\text{6}}.{\text{28}}} \right)\left( {{\text{12}}.{\text{2}}} \right)\cos \left( {{\text{112}}.{\text{8}}^\circ } \right) \cr & {\text{Use a calculator}} \cr & {a^2} \approx 247.6581883 \cr & {\text{Take square roots and choose the positive root}} \cr & a \approx 15.7{\text{m}} \cr & \cr & {\text{Calculate the angle }}B{\text{ using the law of sines}} \cr & \frac{b}{{\sin B}} = \frac{a}{{\sin A}} \cr & \sin B = \frac{{b\sin A}}{a} \cr & \sin B = \frac{{{\text{6}}.{\text{28}}\sin \left( {{\text{112}}.{\text{8}}^\circ } \right)}}{{15.7}} \cr & {\text{Use a calculator}} \cr & \sin B \approx 0.3687452606 \cr & {\text{Use the inverse sine function}} \cr & B = {21.6^ \circ } \cr & \cr & {\text{Calculate }}C \cr & C = {180^ \circ } - A - B \cr & C = {180^ \circ } - {\text{112}}.{\text{8}}^\circ - {21.6^ \circ } \cr & C = {45.6^ \circ } \cr & \cr & {\text{Answer}} \cr & a = 15.7{\text{m}},{\text{ }}B = {21.6^ \circ },\,\,C = {45.6^ \circ } \cr} $$
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