Answer
$$\sqrt 3 {\text{ sq unit}}$$
Work Step by Step
$$\eqalign{
& {\text{From the triangle we have:}} \cr
& A = {60^ \circ },\,\,\,C = {60^ \circ } \cr
& a = 2,\,\,\,b = 2,\,\,\,c = 2,\,\,\,h = \sqrt 3 \cr
& {\text{Find the area of the triangle using the formula }}A = \frac{1}{2}bh \cr
& Area = \frac{1}{2}\left( 2 \right)\left( {\sqrt 3 } \right) \cr
& Area = \sqrt 3 {\text{ sq unit}} \cr
& {\text{Find the area of the triangle using the formula }}A = \frac{1}{2}ab\sin C \cr
& Area = \frac{1}{2}\left( 2 \right)\left( 2 \right)\sin \left( {{{60}^ \circ }} \right) \cr
& Area = \frac{1}{2}\left( 2 \right)\left( 2 \right)\left( {\frac{{\sqrt 3 }}{2}} \right) \cr
& Area = \sqrt 3 {\text{ sq unit}} \cr
& {\text{Both results are the same}} \cr} $$
