Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - Test - Page 740: 6

Answer

$-\frac{\sqrt {2-\sqrt 2}}{2}$

Work Step by Step

With $22.5^\circ=\frac{45^\circ}{2}$, use the half-angle identity, we have $sin(-22.5^\circ)=-sin(22.5^\circ)=-\sqrt {\frac{1-cos(45^\circ)}{2}}=-\sqrt {\frac{1-\frac{\sqrt 2}{2}}{2}}=-\frac{\sqrt {2-\sqrt 2}}{2}$
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