#### Answer

Positive sign

#### Work Step by Step

$\theta =58^{0}\left( Q1;0\leq \theta \leq 90\right) $
Angle is located in quadrant 1 so we should choose positive sign
(Cosine is positive in quadrant 1)

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

Positive sign

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