#### Answer

E

#### Work Step by Step

$\sin \left( \dfrac {\pi }{2}-x\right) =\sin \dfrac {\pi }{2}\cos x-\cos \dfrac {\pi }{2}\sin x=1\times \cos x-0\times \sin x=\cos x\Rightarrow 4\rightarrow E$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

E

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