Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - 6.2 The Unit Circle and Circular Functions - 6.2 Exercises: 22

Answer

$\color{blue}{\sec{(\frac{2\pi}{3})}=-2}$

Work Step by Step

Figure 13 on page 579 of this book shows that the unit circle point $(-\frac{1}{2}, \frac{\sqrt3}{2})$ corresponds to the real number $\dfrac{2\pi}{3}$. RECALL: (i) $\cos{s} = x$ (ii) $\sin{s} = y$ (iii) $\tan{s}=\dfrac{y}{x}$ (iv) $\sec{s} =\dfrac{1}{x}$ Use the coordinates of the unit circle point above and the formula in (iv) above to obtain: $\color{blue}{\sec{(\frac{2\pi}{3})}=\frac{1}{-\frac{1}{2}}=1 \cdot (-2)=-2}$
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