Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - 6.1 Radian Measures - 6.1 Exercises: 63

Answer

The given statement is true because the angle measure is not in degrees.

Work Step by Step

$\sin{30^o}=\dfrac{1}{2}$. However, $\sin{30}\approx-0.9880$. The given statement is true because the angle measure is $30$ radians, not 30 degrees.
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