Answer
$8800\ ft$
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Work Step by Step
1. Draw a diagram as shown in the figure.
2. Angel $B=26^\circ$ and $tanB=\frac{h}{14000}$, thus $h=14000tan(26^\circ)\approx6800\ ft$
3. The elevation of the top is $6800+2000\approx8800\ ft$
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