Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.2 Trigonometric Functions - 5.2 Exercises - Page 519: 93

Answer

$\frac{\sqrt 2}{2}$

Work Step by Step

$\sin\theta=\frac{1}{\csc\theta}=\frac{1}{\frac{\sqrt 8}{2}}=\frac{2}{\sqrt 8}$ $=\frac{2}{2\sqrt 2}=\frac{1}{\sqrt 2}=\frac{\sqrt 2}{2}$
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