Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.6 Applications and Models of Exponential Growth and Decay - 4.6 Exercises - Page 479: 7

Answer

$C$

Work Step by Step

Step 1. The decay function is $y=y_0e^{-0.0241\ t}$ Step 2. Half-life means the time needed for $y=\frac{1}{2}y_0$, we have $\frac{1}{2}y_0=y_0e^{-0.0241\ t}$ and we need to solve for $t$. Step 3. The answer is $C$
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