Answer
$1.8$
Work Step by Step
Apply logarithmic property : $\log m+ \log n=\log (mn)$
We can write the equation as:
$ pH=-\log [1.6 \times 10^{-2}] =-[\log 1.6 + \log 10^{-2}]$
Now, apply logarithmic property : $\log a^ b=b \log a$
Therefore, our answer is: $-[\log 1.6 - 2 \log 10]=-0.204-2= 1.8$