Answer
not one-to-one
Work Step by Step
This function $f(x)=x^2+8$ is not one-to-one, because $y=x^2+8\longrightarrow x^2=y-8\longrightarrow x=\pm\sqrt {y-8}$. There are two $x$ values for some $y$.
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 4 - Inverse, Exponential, and Logarithmic Functions - 4.1 Inverse Functions - 4.1 Exercises - Page 418: 65
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
