## Precalculus (6th Edition)

The red graph contains the following points : $(-2. 0)$ and approximately $(-2.5)$. The blue graph contains the following points : $(2, 0)$ and approximately $(0, 2.5)$. Since the red graph contains $(-2, 0)$, its inverse must contain $(0, -2)$. However, the blue graph does not contain $(0, -2)$. Thus, the two functions graphed are not inverses of each other.