Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 3 - Polynomial and Rational Functions - Test - Page 404: 22

Answer

$\frac{640}{9}\approx71.1\ kg$

Work Step by Step

Step 1. Since $w$ varies inversely as the square of $d$, we can write $w=\frac{c}{d^2}$ where $c$ is a constant. Step 2. As $w=90\ kg$ when $d=6400\ km$, we have $90=\frac{c}{6400^2}$, thus $c=90\cdot 6400^2$ Step 3. For $d=6400+800=7200\ km$, we have $w=\frac{90\cdot 6400^2}{7200^2}=\frac{640}{9}\approx71.1\ kg$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.