Answer
See graph.
Work Step by Step
Step 1. Given $f(x)=(x-2)^2(x+3)$, we can find its zeros as $x=2$ (multiplicity 2) and $x=-3$, y-intercept $f(0)=12$. Function is neither even nor odd. End behavior: rise to the right and fall to the left. Maximum of turning points $2$.
Step 2. Use the information above and test point to graph the function as shown in the figure.