## Precalculus (6th Edition)

In both cases, the product is $12$.
The two ordered pairs in Exercise 4 are: $(3, 4)$ and $(6, 2)$ Multiplying the $y$-value by the $x$ value in each pair gives: For $(3, 4)$: $3(4)=12$ For $(6, 2)$: $6(2)=12$ Both cases give a product of $12$.