Answer
$V.A.$ $x=-\frac{1}{2}$,
$H.A$ $y=-\frac{3}{2}$,
$O.A.$ $none$.
Work Step by Step
Given $f(x)=\frac{4-3x}{2x+1}=\frac{-3x+4}{2x+1}$, we can identify the following:
vertical asymptote $V.A.$ $x=-\frac{1}{2}$,
horizontal asymptote $H.A$ $y=-\frac{3}{2}$,
oblique asymptote $O.A.$ $none$.