Answer
vertical asymptote $x=-2$.
horizontal asymptote $y=-4$.
Work Step by Step
Step 1. Rewrite the equation as $y=\frac{1-4(x+2)^2}{(x+2)^2}=\frac{-4x^2-16x-15}{(x+2)^2}$.
Step 2. We can identify its vertical asymptote as $x=-2$.
Step 3. We can identify its horizontal asymptote as $y=-4$.