Answer
$-(x+6)(x+1)^2(x-3)(x-5)$
Work Step by Step
Step 1. We can identify zeros as $x=-6,-1,-1,3,5$
Step 2. We can factor the function as $f(x)=-(x+6)(x+1)(x+1)(x-3)(x-5)=-(x+6)(x+1)^2(x-3)(x-5)$
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