Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - Summary Exercises on Graphs, Circles, Functions, and Equations - Exercises - Page 248: 27

Answer

(a) domain $[-7,3]$, range $[-5,5]$. (b) not a function.

Work Step by Step

(a) Given $(x+2)^2+y^2=25$, we can identify it as a circle with center at $(-2,0)$ and radius $5$, and we can find its domain as $[-7,3]$, range as $[-5,5]$. (b) We can rewrite the equation as $y^2=25-(x+2)^2$ and $y=\pm\sqrt {25-(x+2)^2}$ which does not represent a function.
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