## Precalculus (6th Edition)

$\color{blue}{y+5=-\frac{5}{6}(x-3)}$ Refer to the graph below.
RECALL: The point-slope form of a line's equation is $y-y_1=m)x-x_1)$ where $m$=slope and $(x_1, y_1)$ is a point in the line. The given line has slope of $-\frac{5}{6}$ and contains the point $(3, -5)$. Thus, the point-slope form of the line's equation is: $y-(-5)=-\frac{5}{6}(x-3) \\\color{blue}{y+5=-\frac{5}{6}(x-3)}$ Refer to the graph in the answer part above.