## Precalculus (6th Edition)

Published by Pearson

# Chapter 2 - Graphs and Functions - Summary Exercises on Graphs, Circles, Functions, and Equations - Exercises - Page 248: 13

#### Answer

$\color{blue}{y+5=-\frac{5}{6}(x-3)}$ Refer to the graph below.

#### Work Step by Step

RECALL: The point-slope form of a line's equation is $y-y_1=m)x-x_1)$ where $m$=slope and $(x_1, y_1)$ is a point in the line. The given line has slope of $-\frac{5}{6}$ and contains the point $(3, -5)$. Thus, the point-slope form of the line's equation is: $y-(-5)=-\frac{5}{6}(x-3) \\\color{blue}{y+5=-\frac{5}{6}(x-3)}$ Refer to the graph in the answer part above.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.