Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - Summary Exercises on Graphs, Circles, Functions, and Equations - Exercises - Page 248: 13

Answer

$\color{blue}{y+5=-\frac{5}{6}(x-3)}$ Refer to the graph below.
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Work Step by Step

RECALL: The point-slope form of a line's equation is $y-y_1=m)x-x_1)$ where $m$=slope and $(x_1, y_1)$ is a point in the line. The given line has slope of $-\frac{5}{6}$ and contains the point $(3, -5)$. Thus, the point-slope form of the line's equation is: $y-(-5)=-\frac{5}{6}(x-3) \\\color{blue}{y+5=-\frac{5}{6}(x-3)}$ Refer to the graph in the answer part above.
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