Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - Summary Exercises on Graphs, Circles, Functions, and Equations - Exercises - Page 248: 13


$\color{blue}{y+5=-\frac{5}{6}(x-3)}$ Refer to the graph below.

Work Step by Step

RECALL: The point-slope form of a line's equation is $y-y_1=m)x-x_1)$ where $m$=slope and $(x_1, y_1)$ is a point in the line. The given line has slope of $-\frac{5}{6}$ and contains the point $(3, -5)$. Thus, the point-slope form of the line's equation is: $y-(-5)=-\frac{5}{6}(x-3) \\\color{blue}{y+5=-\frac{5}{6}(x-3)}$ Refer to the graph in the answer part above.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.