## Precalculus (6th Edition)

$d(A, B)=\sqrt{41}$
The distance $d$ between the points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula: $$d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$$ Use the formula above to obtain: $d(A, B)=\sqrt{(-4-(-8))^2+(2-(-3))^2} \\d(A, B)=\sqrt{(-4+8)^2+(2+3)^2} \\d(A, B)=\sqrt{4^2+5^2} \\d(A, B)=\sqrt{16+25} \\d(A, B)=\sqrt{41}$