Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - Chapter 2 Test Prep - Review Exercises - Page 296: 4

Answer

Yes, $(5,7)$

Work Step by Step

Step 1. Given $A(5,7), B(3,9)$, the distance between the points is $d(A,B)=\sqrt {(5-3)^2+(7-9)^2}=2\sqrt {2}$ Step 2. Given $B(3,9), C(6,8)$, the distance between the points is $d(B,C)=\sqrt {(6-3)^2+(8-9)^2}=\sqrt {10}$ Step 3. Given $A(5,7), C(6,8)$, the distance between the points is $d(A,C)=\sqrt {(6-5)^2+(8-7)^2}=\sqrt 2$ Step 4. Since $(d(B,C))^2=(d(A,B))^2+(d(A,C))^2$, based on the Pythagorean theorem, the three points form a right triangle with point $A(5,7)$ being the right angle
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