Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.4 Linear Functions - 2.4 Exercises - Page 233: 91


The midpoint of the first and last points in the table and the middle entry in the table are the same.

Work Step by Step

RECALL: The coordinates of the midpoint of the points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula: $=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$ Use the formula above to obtain: midpoint $=\left(\frac{0+6}{2}, \frac{-6+12}{2}\right)=\left(\frac{6}{2}, \frac{6}{2}\right)=(3., 3)$ The middle entry in the given table is $(3, 3)$. Thus, the midpoint of the first and last point in the table is the same as the middle entry in the table.
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