Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - Summary Exercises on Sequences and Series - Exercises - Page 1038: 23

Answer

$144$

Work Step by Step

1. We can identify the sequence as arithmetical with $a_1=1, d=2$ 2. We have $\sum_{j=1}^{12}(2j-1)=\frac{12}{2}(1+2(12)-1)=144$
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