## Precalculus (6th Edition)

$a)A_{10}=0.01\times 2^{10-1}=0,01\times 2^{9}=5.12\$ ;b)S_{n}=0.01\times \left( 2^{10}-1\right) =10.23\
Amount earned on the indicated day can be calculated with using simple geometric sequence formula $A_{n}=0.01\times 2^{n-1}$ And the total amount earned will be $S_{n}=\dfrac {A_{1}\left( 1-r^{n}\right) }{1-r}=\dfrac {0.01\times \left( 1-2^{n}\right) }{1-2}=0.01\left( 2^{n}-1\right)$ $\Rightarrow a)A_{10}=0.01\times 2^{10-1}=0,01\times 2^{9}=5.12\$ ;b)S_{n}=0.01\times \left( 2^{10}-1\right) =10.23\