Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 10 - Analytic Geometry - 10.3 Hyperbolas - 10.3 Exercises - Page 987: 7

Answer

$${\bf{D}}$$

Work Step by Step

$$\eqalign{ & \frac{{{x^2}}}{9} - \frac{{{y^2}}}{{25}} = 1 \cr & {\text{This equation is written in the form }}\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} = 1 \cr & {\text{With }}a = 3,\,\,b = 5{\text{ }} \cr & {\text{,then the graph of this equation is a hyperbola centered at }}\left( {0,0} \right) \cr & {\text{Tranverse axis: horizontal}} \cr & {\text{Vertices: }}\left( { \pm a,0} \right):\left( { \pm 3,0} \right) \cr & {\text{Therefore, the graph in the column II is }}{\bf{D}} \cr} $$
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