Answer
$${\bf{B}}$$
Work Step by Step
$$\eqalign{
& \frac{{{{\left( {y + 1} \right)}^2}}}{{25}} - \frac{{{{\left( {x + 2} \right)}^2}}}{9} = 1 \cr
& {\text{This equation is written in the form }}\frac{{{{\left( {y - k} \right)}^2}}}{{{a^2}}} - \frac{{{{\left( {x - h} \right)}^2}}}{{{b^2}}} = 1 \cr
& {\text{With: }}h = - 2,\,\,\,y = - 1 \cr
& ,{\text{Then}} \cr
& {\text{Tranverse axis: vertical}} \cr
& {\text{Center: }}\left( {h,k} \right):\left( { - 2, - 1} \right) \cr
& {\text{Therefore, the solution in the column II is }}{\bf{B}} \cr} $$
