Answer
$\frac{-1\pm\sqrt {5}i}{3}$,
Work Step by Step
Step 1. Rewrite the equation as $3x^2+2x+2=0$, we have $a=3, b=2, c=2$
Step 2. Use the quadratic formula $x=\frac{-b\pm\sqrt {b^2-4ac}}{2a}$, we have
$x=\frac{-2\pm\sqrt {2^2-4(3)(2)}}{2(3)}=\frac{-2\pm\sqrt {-20}}{2(3)}=\frac{-1\pm\sqrt {5}i}{3}$,
