## Precalculus (6th Edition)

$y=\dfrac{3x}{a-1}$
Put all the terms with $y$ on the left side of the equation: $ay+2x=y+5x \\ay+2x-2x-y=y+5x-2x-y \\ay-y=3x$ Factor out $y$ on the left side of the equation: $y(a-1)=3x$ Divide $a-1$ to both sides of the equation: $\dfrac{y(a-1)}{a-1}=\dfrac{3x}{a-1} \\y=\dfrac{3x}{a-1}$