Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Chapter 1 Test Prep - Review Exercises - Page 181: 116

Answer

$(-\frac{22}{3},\frac{14}{3})$

Work Step by Step

Step 1. We can remove the absolute sign to get: $-3\lt\frac{1}{2}x+\frac{2}{3}\lt3$ Step 2. Multiply $6$ to the entire inequality to get $-18\lt 3x+4\lt18\longrightarrow -22\lt 3x\lt14\longrightarrow -\frac{22}{3}\lt x\lt\frac{14}{3}$ or in interval notation $(-\frac{22}{3},\frac{14}{3})$
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