Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.8 Absolute Value Equations and Inequalities - 1.8 Exercises - Page 168: 68

Answer

$|r-s|=6$.

Work Step by Step

The distance between $r$ and $s$ is the positive value of $r-s$ or $s-r$, thus we have $|r-s|=6$.
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