Answer
$[-\frac{8}{3},\frac{3}{2}]U(6,\infty)$
Work Step by Step
Step 1. Identify the boundary points as $x=-\frac{8}{3},\frac{3}{2},6$
Step 2. Use test points at $x=-3,0,2,7$, the signs of the left side rational are $-,+,-,+$
Step 3. The inequality is true for positive (2nd and 4th regions, excluding $x=6$), thus the solutions are $[-\frac{8}{3},\frac{3}{2}]U(6,\infty)$
