Answer
$b=\pm\sqrt {c^2-a^2}$
Work Step by Step
Step 1. Given $a^2+b^2=c^2$, we have $b^2=c^2-a^2$
Step 2. Take square root on both sides, we have $b=\pm\sqrt {c^2-a^2}$
Step 3. In the case of Pythagorean theorem, use the $+$ sign only.
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 1 - Equations and Inequalities - 1.6 Other Types of Equations and Applications - 1.6 Exercises - Page 149: 110
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