Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.5 Applications and Modeling with Quadratic Equations - 1.5 Exercises - Page 133: 47

Answer

(a) $0.19\ and \ 10.92\ sec$ (b) $11.32\ sec$.

Work Step by Step

(a) Given $s=-2.7t^2+30t+6.5$, let $s=12$, we have $12=-2.7t^2+30t+6.5$ or $2.7t^2-30t+5.5=0$ which can be solved using the quadratic formula to get $t\approx0.19\ and \ 10.92\ sec$ (b) For reaching the surface, we have $s=0$, thus $0=-2.7t^2+30t+6.5$ or $2.7t^2-30t-6.5=0$ which gives $t\approx11.32\ sec$. (Discard the negative answer.)
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