Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set - Page 31: 114

Answer

$$\frac{x^{26}y^6}{4}$$

Work Step by Step

\begin{align} \\ & \frac{(2^{-1}x^{-3}y^{-1})^{-2}(2x^{-6}y^4)^{-2}(9x^3y^{-3})^0}{(2x^{-4}y^{-6})^2}\\ & = \frac{(2^2x^6y^2)(2^{-2}x^{12}y^{-8})(9^0x^0y^0)}{2^2x^{-8}y^{-12}}\\ &= \frac{2^0x^{18}y^{-6}}{2^2x^{-8}y^{-12}} \\ &= \frac{x^{18}x^8y^{-6}y^{12}}{2^2} \\ &= \frac{x^{26}y^6}{4} \end{align}
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