Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 145: 150

Answer

length $5$ yards, width $3$ yards.

Work Step by Step

Step 1. Assume the length is $x$ yards; then the width would be $2x-7$ yards. Step 2. The area of the room is given by $x(2x-7)=15$; we have $2x^2-7x-15=0$ Step 3. Factor the equation to get $(2x+3)(x-5)=0$; choose the positive solution to get $x=5$ yards. Step 4. Thus the length is $5$ yards and the width is $3$ yards.
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