Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 144: 135

Answer

$\{2\}$

Work Step by Step

Step 1. Rewrite the equation to isolate the radical. We have $\sqrt {8-2x}=x$ Step 2. Take the square on both sides to get $8-2x=x^2$, $x^2+2x-8=0$ and $(x+4)(x-2)=0$ Step 3. Test the solutions $x=-4, 2$ in the original equation. We should discard $x=-4$ and keep $x=2$ as the answer.
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