Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 5 - Section 5.2 - Sum and Difference Formulas - Exercise Set - Page 671: 88


The graphs appear to coincide.

Work Step by Step

Please note that$$\cos (\alpha - \beta )= \cos \alpha \cos \beta + \sin \alpha \sin \beta .$$So we have$$\cos( \frac{3\pi }{2}-x)= \cos \frac{3\pi }{2} \cos x + \sin \frac{3\pi }{2} \sin x=-\sin x.$$
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