Answer
The graphs appear to coincide.
Work Step by Step
$$\frac{\sin x}{1- \cos ^2x}= \frac{\sin x}{\sin ^2x}=\frac{1}{\sin x}=\csc x$$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 5 - Section 5.1 - Verifying Trigonometric Identities - Exercise Set - Page 660: 85
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