Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Review Exercises - Page 512: 42

Answer

$(-\infty,3)$

Work Step by Step

Logarithmic functions are defined only for positive arguments. So, the domain of f is defined with $3-x \gt 0\qquad $... solve (isolate x) ... add x to both sides $ 3 \gt x\qquad $ ... or,$\qquad x \lt 3$ The domain of $ f $ is $(-\infty,3)$
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