Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Test - Page 434: 20

Answer

$(-\infty,-3)\cup(-3,\infty)$

Work Step by Step

Step 1. The domain requirement is that the denominator can not be zero, which gives $x\ne-3$. Thus the domain can be written as $(-\infty,-3)\cup(-3,\infty)$ Step 2. See graph.
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