Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.1 - Complex Numbers - Exercise Set: 19

Answer

$ -5 +12i$

Work Step by Step

$(2+3i)^2$ $= 4 + 6i + 6i+ 9i^2$ $= 4+12i+ 9\times (-1)$ $= 4 - 9 + 12i$ $= -5 +12i$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.