Answer
$6i-10j$
Work Step by Step
We know that if $v=ai+bj$ and $w=di+ej$, then $v+w=(a+d)i+(b+e)j$ and that if $z$ is a constant, then $zv=(za)i+(zb)j$.
Hence here: $v_1+2v_2-v_3=(4i+6j)+2(-3i-6j)-(-8i+4j)=4i+6j-6i-12j+8i-4j=6i-10j$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 9 - Polar Coordinates; Vectors - Chapter Review - Chapter Test - Page 636: 19
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