Chapter 9 - Polar Coordinates; Vectors - 9.6 Vectors in Space - 9.6 Assess Your Understanding - Page 626: 70

$(x-1)^2+(y-2)^2+(z-2)^2=4$

If $r$ is the radius and $P_0(x_0,y_0,z_0)$ is the center of the sphere, then the standard form of the equation of the sphere is: $(x-x_0)^2+(y-y_0)^2+(z-z_0)^2=r^2.$ Hence, here: $(x-1)^2+(y-2)^2+(z-2)^2=2^2\\ (x-1)^2+(y-2)^2+(z-2)^2=4\\$