Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.5 Simple Harmonic Motion; Damped Motion; Combining Waves - 8.5 Assess Your Understanding - Page 553: 1

Answer

amplitude = $5$ periods = $\dfrac{\pi}{2}$

Work Step by Step

If a function has form $y=A\sin{(\alpha x)}$, then $|A|$ stands for the amplitude and $T =\frac{2\pi}{\omega}$ stands for the period. Hence, here we have amplitude:$|5|=5$ period: $\frac{2\pi}{4}=\frac{\pi}{2}$.
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