Answer
amplitude = $5$
periods = $\dfrac{\pi}{2}$
Work Step by Step
If a function has form $y=A\sin{(\alpha x)}$, then $|A|$ stands for the amplitude and $T =\frac{2\pi}{\omega}$ stands for the period.
Hence, here we have
amplitude:$|5|=5$
period: $\frac{2\pi}{4}=\frac{\pi}{2}$.