Answer
$\frac{\pi}{2},\frac{7\pi}{6},\frac{11\pi}{6}$
Work Step by Step
Step 1. Factor the equation to get $(2sin\theta+1)(sin\theta-1)=0$, thus $sin\theta=1$ or $sin\theta=-\frac{1}{2}$
Step 2. For $sin\theta=1$, we have $\theta=2kpi+\frac{\pi}{2}$
Step 3. For $sin\theta=-\frac{1}{2}$, we have $\theta=2kpi+\frac{7\pi}{6}$ and $\theta=2kpi+\frac{11\pi}{6}$
Step 4. Within $[0,2\pi)$ we have $\theta=\frac{\pi}{2},\frac{7\pi}{6},\frac{11\pi}{6}$
